What is (\partial)/(\partial y)(y+z) ?

The answer to (\partial)/(\partial y)(y+z) is 1

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(\partial)/(\partial y)(y+z)

\frac{\partial}{\partial y} (y + z)

1

Solution steps

\frac{\partial}{\partial y} (y + z)

Treat

z

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (z) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} ((sin (x))^{3 x})

x \to 0 lim (\frac{sin ( 8 x )}{8})

\frac{1}{2 x - 1}

f^{^{'}} (x) = - 2

\int \frac{x - 2}{x ^{2} + x - 1} d x

What is (\partial)/(\partial y)(y+z) ?
The answer to (\partial)/(\partial y)(y+z) is 1