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Popular >

y^'=y^2(3+x)

Solution

y^{^{'}} = y^{2} (3 + x)

Solution

y = - \frac{2}{6 x + x ^{2} + c _{1}}

Solution steps

y^{'} (x) = y^{2} (3 + x)

Solve separable ODE:

y = - \frac{2}{6 x + x ^{2} + c _{1}}

y = - \frac{2}{6 x + x ^{2} + c _{1}}

Popular Examples

integral of cos^2(2ax)

\int cos^{2} (2 a x) d x

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\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + x - 2})

derivative of (e^{4x^2}/(x^2))

\frac{d}{d x} (\frac{e ^{4 x^{2}}}{x ^{2}})

area x^2-10,9x area

x^{2} - 10, 9 x

integral of 1/(sqrt(e^{2x)-4)}

\int \frac{1}{e ^{2 x} - 4} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2(3+x) ?
The solution for y^'=y^2(3+x) is y=-2/(6x+x^2+c_{1)}