What is the limit as x approaches 1 of+(1/(x^2-1)) ?

The limit as x approaches 1 of+(1/(x^2-1)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of+(1/(x^2-1))

x \to 1 lim (+ (\frac{1}{x ^{2} - 1}))

diverges

Solution steps

x \to 1 lim (\frac{1}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{1}{x ^{2} - 1}) = \infty

x \to 1 - lim (\frac{1}{x ^{2} - 1}) = - \infty

= diverges

\int 3 x d x

\int sin^{2} (2 x) cos^{2} (x) d x

x \to 0 lim ((1 - 10 x)^{\frac{1}{x}})

x \to \infty + lim (x^{(3)} e^{(- x^{(2)})})

\frac{d y}{d x} y = \frac{2 cos ( x )}{1 + sin ( x )}

What is the limit as x approaches 1 of+(1/(x^2-1)) ?
The limit as x approaches 1 of+(1/(x^2-1)) is diverges