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Popular >

y^'+4y=-1

Solution

y^{^{'}} + 4 y = - 1

Solution

y = \frac{e ^{- 4 t - c_{1}}}{4} - \frac{1}{4}

Solution steps

y^{'} (t) + 4 y = - 1

Solve separable ODE:

y = \frac{e ^{- 4 t - c_{1}}}{4} - \frac{1}{4}

y = \frac{e ^{- 4 t - c_{1}}}{4} - \frac{1}{4}

Popular Examples

(dy)/(dx)=(sqrt(y)-y)/(tan(x))

\frac{d y}{d x} = \frac{y - y}{tan ( x )}

integral of 8sec^3(5x)

\int 8 sec^{3} (5 x) d x

limit as x approaches 7+of 5/(x-7)

x \to 7 + lim (\frac{5}{x - 7})

y^{^{'}} (x^{2} + 1) = y

derivative of (sqrt(x)+1/(sqrt(x))^2)

\frac{d}{d x} ((x + \frac{1}{x})^{2})

Frequently Asked Questions (FAQ)

What is the solution for y^'+4y=-1 ?
The solution for y^'+4y=-1 is y=(e^{-4t-c_{1}})/4-1/4