What is the derivative of x^4+3x^2 ?

The derivative of x^4+3x^2 is 4x^3+6x

What is the first derivative of x^4+3x^2 ?

The first derivative of x^4+3x^2 is 4x^3+6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{4} + 3 x^{2})

4 x^{3} + 6 x

Solution steps

\frac{d}{d x} (x^{4} + 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x^{2}) = 6 x

= 4 x^{3} + 6 x

f (x) = x^{4} + 3 x^{3}, at x = 1

n = 1 \sum \infty \frac{2}{5 ^{n - 1}}

\int 2 x e^{x^{2} - 1} d x

\frac{d}{d x} ((x^{2} + 2)^{\frac{1}{2}})

\int (x + \frac{1}{2 x}) d x

What is the derivative of x^4+3x^2 ?
The derivative of x^4+3x^2 is 4x^3+6x
What is the first derivative of x^4+3x^2 ?
The first derivative of x^4+3x^2 is 4x^3+6x