What is the integral of 0.1e^{-x/(10)} ?

The integral of 0.1e^{-x/(10)} is -e^{-x/(10)}+C

Popular >

integral of 0.1e^{-x/(10)}

\int 0.1 e^{- \frac{x}{10}} d x

- e^{- \frac{x}{10}} + C

Solution steps

\int 0.1 e^{- \frac{x}{10}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.1 \cdot \int e^{- \frac{x}{10}} d x

Apply u-substitution

: \int - 10 e^{u} d u

= 0.1 \cdot \int - 10 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.1 (- 10 \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 0.1 (- 10 e^{u})

Substitute back

u = - \frac{x}{10}

= 0.1 (- 10 e^{- \frac{x}{10}})

Simplify

= - e^{- \frac{x}{10}}

Add a constant to the solution

= - e^{- \frac{x}{10}} + C

\frac{1}{x ^{2} + x + 1}

\int (5 + x^{9})^{6} x^{8} d x

\frac{d}{d x} (2 x^{3} cos (3 x))

x \to 1 lim (6 x + a)

\frac{\partial}{\partial x} ((\frac{x}{y}) - yz)

What is the integral of 0.1e^{-x/(10)} ?
The integral of 0.1e^{-x/(10)} is -e^{-x/(10)}+C