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Popular >

y^'+y/x = 1/x

Solution

y^{^{'}} + \frac{y}{x} = \frac{1}{x}

Solution

y = \frac{c _{1}}{x} + 1

Solution steps

y^{'} (x) + \frac{y}{x} = \frac{1}{x}

Solve separable ODE:

y = \frac{c _{1}}{x} + 1

y = \frac{c _{1}}{x} + 1

Popular Examples

(\partial)/(\partial x)(ln(2+sin(xy)))

\frac{\partial}{\partial x} (ln (2 + sin (x y)))

(\partial)/(\partial z)(zx^2)

\frac{\partial}{\partial z} (z x^{2})

(dy)/(dx)=sin(x)(cos(2y)-cos^2(y))

\frac{d y}{d x} = sin (x) (cos (2 y) - cos^{2} (y))

sum from n=1 to infinity of (n-1)/(n!)

n = 1 \sum \infty \frac{n - 1}{n !}

limit as x approaches infinity of (e^{5x}+x^2)/(e^{5x)-x}

x \to \infty lim (\frac{e ^{5 x} + x ^{2}}{e ^{5 x} - x})

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x = 1/x ?
The solution for y^'+y/x = 1/x is y=(c_{1})/x+1