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Popular >

derivative of y=(x-1)/(x+1)

Solution

derivative of

y = \frac{x - 1}{x + 1}

Solution

\frac{2}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 1}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 1 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x - 1 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x - 1) = 1

\frac{d}{d x} (x + 1) = 1

= \frac{1 \cdot ( x + 1 ) - 1 \cdot ( x - 1 )}{( x + 1 ) ^{2}}

Simplify

\frac{1 \cdot ( x + 1 ) - 1 \cdot ( x - 1 )}{( x + 1 ) ^{2}} : \frac{2}{( x + 1 ) ^{2}}

= \frac{2}{( x + 1 ) ^{2}}

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limit as x approaches 0-of arccos(e^{-x^2})

x \to 0 - lim (arccos (e^{- x^{2}}))

tangent of (x+2)^2+(y-3)^2=37,(-3,-3)tangent of

(x + 2)^{2} + (y - 3)^{2} = 37, (- 3, - 3)

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\int_{0}^{\frac{π}{4}} 3 cos^{5} (2 x) d x

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\int - 2 t cos (t) d t

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\int 48 t^{7} e^{- t^{8}} d t

Frequently Asked Questions (FAQ)

What is the derivative of y=(x-1)/(x+1) ?
The derivative of y=(x-1)/(x+1) is 2/((x+1)^2)
What is the first derivative of y=(x-1)/(x+1) ?
The first derivative of y=(x-1)/(x+1) is 2/((x+1)^2)