What is the derivative of 3x^2-4x ?

The derivative of 3x^2-4x is 6x-4

What is the first derivative of 3x^2-4x ?

The first derivative of 3x^2-4x is 6x-4

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\frac{d}{d x} (3 x^{2} - 4 x)

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

= 6 x - 4

\frac{\partial}{\partial y} (2 x^{2} y)

\int_{1}^{2} x sin (π x) d x

\frac{d y}{d t} + 2 y = e^{- t} cos (3 t), y (0) = 0

\int \frac{16}{( 64 x ^{2} + 1 ) ^{2}} d x

f (x) = (x + 3)^{3}, [- 1, 6]

What is the derivative of 3x^2-4x ?
The derivative of 3x^2-4x is 6x-4
What is the first derivative of 3x^2-4x ?
The first derivative of 3x^2-4x is 6x-4