What is the derivative of (x^2-4^3) ?

The derivative of (x^2-4^3) is 6x(x^2-4)^2

What is the first derivative of (x^2-4^3) ?

The first derivative of (x^2-4^3) is 6x(x^2-4)^2

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\frac{d}{d x} ((x^{2} - 4)^{3})

6 x (x^{2} - 4)^{2}

Solution steps

\frac{d}{d x} ((x^{2} - 4)^{3})

Apply the chain rule:

3 (x^{2} - 4)^{2} \frac{d}{d x} (x^{2} - 4)

= 3 (x^{2} - 4)^{2} \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= 3 (x^{2} - 4)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} - 4)^{2}

\frac{d}{d x} (e^{x} x + 3 e^{x})

\frac{d}{d x} (2 x cos (y))

\frac{12}{x ^{3}}

\int - 8 d x

15 t^{2}

What is the derivative of (x^2-4^3) ?
The derivative of (x^2-4^3) is 6x(x^2-4)^2
What is the first derivative of (x^2-4^3) ?
The first derivative of (x^2-4^3) is 6x(x^2-4)^2