What is the derivative of y=e^{3tsin(2t)} ?

The derivative of y=e^{3tsin(2t)} is e^{3tsin(2t)}*3(sin(2t)+2tcos(2t))

What is the first derivative of y=e^{3tsin(2t)} ?

The first derivative of y=e^{3tsin(2t)} is e^{3tsin(2t)}*3(sin(2t)+2tcos(2t))

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derivative of

y = e^{3 t s i n (2 t)}

e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{3 t s i n (2 t)})

Apply the chain rule:

e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

= e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

\frac{d}{d t} (3 t sin (2 t)) = 3 (sin (2 t) + 2 t cos (2 t))

= e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

\int \frac{1}{( 4 x + 5 )} d x

\int sin (2 x) cos^{2} (2 x) d x

x \frac{d y}{d x} = y - x^{2} + y^{2}

\frac{d}{d x} (\frac{10}{2 x})

What is the derivative of y=e^{3tsin(2t)} ?
The derivative of y=e^{3tsin(2t)} is e^{3tsin(2t)}*3(sin(2t)+2tcos(2t))
What is the first derivative of y=e^{3tsin(2t)} ?
The first derivative of y=e^{3tsin(2t)} is e^{3tsin(2t)}*3(sin(2t)+2tcos(2t))