What is the derivative of 8sin(2x) ?

The derivative of 8sin(2x) is 16cos(2x)

What is the first derivative of 8sin(2x) ?

The first derivative of 8sin(2x) is 16cos(2x)

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derivative of

8 sin (2 x)

16 cos (2 x)

Solution steps

\frac{d}{d x} (8 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 8 cos (2 x) \cdot 2

Simplify

= 16 cos (2 x)

\frac{d}{d x} (\frac{1 + x}{x ^{4}})

\frac{\partial}{\partial x} (5 y^{4} cos (3 x))

\frac{d}{d x} (\frac{4 x ^{3} + 6}{x})

\int_{25}^{50} 15 d x

\frac{d}{d x} (3 e^{x} + ln (x) + tan (x))

What is the derivative of 8sin(2x) ?
The derivative of 8sin(2x) is 16cos(2x)
What is the first derivative of 8sin(2x) ?
The first derivative of 8sin(2x) is 16cos(2x)