What is the integral of (\sqrt[3]{1+ln(x)})/x ?

The integral of (\sqrt[3]{1+ln(x)})/x is 3/4 (1+ln(x))^{4/3}+C

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integral of (\sqrt[3]{1+ln(x)})/x

\frac{3}{4} (1 + ln (x))^{\frac{4}{3}} + C

Solution steps

Apply u-substitution

Apply the Power Rule

: \frac{3}{4} u^{\frac{4}{3}}

= \frac{3}{4} u^{\frac{4}{3}}

Substitute back

u = 1 + ln (x)

= \frac{3}{4} (1 + ln (x))^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{4} (1 + ln (x))^{\frac{4}{3}} + C

f (x) = r^{2} - 11 x^{2}

\frac{\partial}{\partial u} (u \cdot v)

- \frac{1}{4} cos^{4} (x)

\int \frac{x ^{4} - 3 x ^{2}}{x ^{5} - 5 x ^{3} - 24} d x

\frac{x}{y}

What is the integral of (\sqrt[3]{1+ln(x)})/x ?
The integral of (\sqrt[3]{1+ln(x)})/x is 3/4 (1+ln(x))^{4/3}+C