What is the derivative of x^3-3x^2-9x+4 ?

The derivative of x^3-3x^2-9x+4 is 3x^2-6x-9

What is the first derivative of x^3-3x^2-9x+4 ?

The first derivative of x^3-3x^2-9x+4 is 3x^2-6x-9

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\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 4)

3 x^{2} - 6 x - 9

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (9 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 3 x^{2} - 6 x - 9 + 0

Simplify

= 3 x^{2} - 6 x - 9

s^{- \frac{3}{2}}

\int x^{2} - 1 d x

(- 2.5) (- 1.2)

y = ln (x x^{2} - 4)

f (x) = x + \frac{1}{x ^{3}}

What is the derivative of x^3-3x^2-9x+4 ?
The derivative of x^3-3x^2-9x+4 is 3x^2-6x-9
What is the first derivative of x^3-3x^2-9x+4 ?
The first derivative of x^3-3x^2-9x+4 is 3x^2-6x-9