What is the derivative of-2cos(x+3x^3) ?

The derivative of-2cos(x+3x^3) is 2sin(x)+9x^2

What is the first derivative of-2cos(x+3x^3) ?

The first derivative of-2cos(x+3x^3) is 2sin(x)+9x^2

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\frac{d}{d x} (- 2 cos (x) + 3 x^{3})

2 sin (x) + 9 x^{2}

Solution steps

\frac{d}{d x} (- 2 cos (x) + 3 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (3 x^{3})

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

= - (- 2 sin (x)) + 9 x^{2}

Simplify

= 2 sin (x) + 9 x^{2}

\frac{d}{d x} (x^{2} + 5 x)

\int_{0}^{π} sin (\frac{x}{2}) d x

\int \frac{1 + x ^{2} + 1}{( x ^{2} + 1 ) ^{\frac{3}{2}}} d x

\int 17 x e^{- x^{2}} d x

\frac{d y}{d x} = \frac{cos ( 13 x )}{e ^{13 y}}

What is the derivative of-2cos(x+3x^3) ?
The derivative of-2cos(x+3x^3) is 2sin(x)+9x^2
What is the first derivative of-2cos(x+3x^3) ?
The first derivative of-2cos(x+3x^3) is 2sin(x)+9x^2