What is the solution for (dy)/(dx)-4y=2xy^2 ?

The solution for (dy)/(dx)-4y=2xy^2 is y=(8e^{4x})/(-4e^{4x)x+e^{4x}+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)-4y=2xy^2

\frac{d y}{d x} - 4 y = 2 x y^{2}

y = \frac{8 e ^{4 x}}{- 4 e ^{4 x} x + e ^{4 x} + c _{1}}

Solution steps

\frac{d y}{d x} - 4 y = 2 x y^{2}

Solve Bernoulli ODE:

y = \frac{8 e ^{4 x}}{- 4 e ^{4 x} x + e ^{4 x} + c _{1}}

y = \frac{8 e ^{4 x}}{- 4 e ^{4 x} x + e ^{4 x} + c _{1}}

sin (x^{k})

\int_{0}^{l n (2)} \frac{3}{e ^{x} + 4} d x

f (x) = x^{2} - 4 x - 4

\frac{d}{d x} (0^{4})

\frac{d}{d x} ((5 x^{3} - 1)^{3} ln (x^{2} + 1))

What is the solution for (dy)/(dx)-4y=2xy^2 ?
The solution for (dy)/(dx)-4y=2xy^2 is y=(8e^{4x})/(-4e^{4x)x+e^{4x}+c_{1}}