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Popular >

y^'+2y-y^2=0

Solution

y^{^{'}} + 2 y - y^{2} = 0

Solution

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

Solution steps

y^{'} (t) + 2 y - y^{2} = 0

Solve Bernoulli ODE:

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y-y^2=0 ?
The solution for y^'+2y-y^2=0 is y= 2/(-e^{2t+c_{1)}+1}