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Popular >

derivative of y=(x^2+x+1)^{100}

Solution

derivative of

y = (x^{2} + x + 1)^{100}

Solution

100 (x^{2} + x + 1)^{99} (2 x + 1)

Solution steps

\frac{d}{d x} ((x^{2} + x + 1)^{100})

Apply the chain rule:

100 (x^{2} + x + 1)^{99} \frac{d}{d x} (x^{2} + x + 1)

= 100 (x^{2} + x + 1)^{99} \frac{d}{d x} (x^{2} + x + 1)

\frac{d}{d x} (x^{2} + x + 1) = 2 x + 1

= 100 (x^{2} + x + 1)^{99} (2 x + 1)

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Frequently Asked Questions (FAQ)

What is the derivative of y=(x^2+x+1)^{100} ?
The derivative of y=(x^2+x+1)^{100} is 100(x^2+x+1)^{99}(2x+1)
What is the first derivative of y=(x^2+x+1)^{100} ?
The first derivative of y=(x^2+x+1)^{100} is 100(x^2+x+1)^{99}(2x+1)