What is the derivative of x^2+1/x ?

The derivative of x^2+1/x is 2x-1/(x^2)

What is the first derivative of x^2+1/x ?

The first derivative of x^2+1/x is 2x-1/(x^2)

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\frac{d}{d x} (x^{2} + \frac{1}{x})

2 x - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{2} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 2 x - \frac{1}{x ^{2}}

(∣ x ∣)^{^{'}}

\frac{\partial}{\partial x} (cos (y) cos (x))

\int arctan (4 x) d x

f (x) = \frac{1 - x}{2 + x}

x \to 2 lim (ln (x - 1))

What is the derivative of x^2+1/x ?
The derivative of x^2+1/x is 2x-1/(x^2)
What is the first derivative of x^2+1/x ?
The first derivative of x^2+1/x is 2x-1/(x^2)