What is the sum from n=4 to infinity of (3^n)/(10^n) ?

The sum from n=4 to infinity of (3^n)/(10^n) is converges

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sum from n=4 to infinity of (3^n)/(10^n)

n = 4 \sum \infty \frac{3 ^{n}}{1 0 ^{n}}

converges

Solution steps

n = 4 \sum \infty \frac{3 ^{n}}{1 0 ^{n}}

n \to \infty lim (n (\frac{\frac{3 ^{n}}{1 0 ^{n}}}{\frac{3 ^{n + 1}}{1 0 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

\int 4 - t^{2} d t

\frac{d}{d y} (4 y - 1)

x \to 3 - lim (x^{2} - 5 x + 6)

f (x) = x^{4} - 20 x^{2} + 64

What is the sum from n=4 to infinity of (3^n)/(10^n) ?
The sum from n=4 to infinity of (3^n)/(10^n) is converges