What is (\partial)/(\partial x)(cos(xy)y) ?

The answer to (\partial)/(\partial x)(cos(xy)y) is -y^2sin(xy)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos(xy)y)

\frac{\partial}{\partial x} (cos (x y) y)

- y^{2} sin (x y)

Solution steps

\frac{\partial}{\partial x} (cos (x y) y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{\partial}{\partial x} (x y)

= - sin (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= y (- sin (x y) y)

Simplify

y (- sin (x y) y) : - y^{2} sin (x y)

= - y^{2} sin (x y)

\frac{d}{d x} (sin^{c o s (x)} (x))

\int \frac{2 e ^{2 t}}{5 + e ^{2 t}} d t

64 x^{2}

ln (2 x) 4

\int_{0}^{\frac{π}{2}} cos^{2} (\frac{x}{2}) d x

What is (\partial)/(\partial x)(cos(xy)y) ?
The answer to (\partial)/(\partial x)(cos(xy)y) is -y^2sin(xy)