What is the tangent of f(x)=3sin(x),\at x=-pi/4 ?

The tangent of f(x)=3sin(x),\at x=-pi/4 is y= 3/(sqrt(2))x-3/(sqrt(2))+(3pi)/(4sqrt(2))

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tangent of f(x)=3sin(x),\at x=-pi/4

tangent of

f (x) = 3 sin (x), at x = - \frac{π}{4}

y = \frac{3}{2} x - \frac{3}{2} + \frac{3 π}{4 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, - \frac{3}{2})

Find the slope of

f (x) = 3 sin (x) : \frac{df ( x )}{d x} = 3 cos (x)

Compute the slope of

f (x) = 3 sin (x)

x = - \frac{π}{4} : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(- \frac{π}{4}, - \frac{3}{2}) : y = \frac{3}{2} x - \frac{3}{2} + \frac{3 π}{4 2}

y = \frac{3}{2} x - \frac{3}{2} + \frac{3 π}{4 2}

y = 80 (1 - e^{- 0.041 x})

\frac{\partial}{\partial x} (y (x^{2} + y)^{6})

x \to - 1 lim (x + 5)

\frac{\partial}{\partial x} (4 x + 2 y)

\frac{d}{d x} (\frac{2}{5 x - 1})

What is the tangent of f(x)=3sin(x),\at x=-pi/4 ?
The tangent of f(x)=3sin(x),\at x=-pi/4 is y= 3/(sqrt(2))x-3/(sqrt(2))+(3pi)/(4sqrt(2))