What is the first (3sin(t))^' ?

The first (3sin(t))^' is 3cos(t)

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(3sin(t))^'

(3 sin (t))^{^{'}}

3 cos (t)

Solution steps

(3 sin (t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 (sin (t))^{^{'}}

Apply the common derivative:

(sin (t))^{'} = cos (t)

= 3 cos (t)

x^{3} - 3 x^{2} + 5 x - 7

\int e^{3 x} 3 d x

\frac{\partial}{\partial y} ((3 x + 3 y) e^{y})

\frac{d}{d x} (5^{x^{2}} ln (tan (x)))

\int x sin (x) + 1 d x