What is the derivative of (2(1+x^2)/((1-x^2)^2)) ?

The derivative of (2(1+x^2)/((1-x^2)^2)) is (4x(x^2+3))/((1-x^2)^3)

What is the first derivative of (2(1+x^2)/((1-x^2)^2)) ?

The first derivative of (2(1+x^2)/((1-x^2)^2)) is (4x(x^2+3))/((1-x^2)^3)

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\frac{d}{d x} (\frac{2 ( 1 + x ^{2} )}{( 1 - x ^{2} ) ^{2}})

\frac{4 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 ( 1 + x ^{2} )}{( 1 - x ^{2} ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1 + x ^{2}}{( 1 - x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( 1 + x ^{2} ) ( 1 - x ^{2} ) ^{2} - \frac{d}{d x} ( ( 1 - x ^{2} ) ^{2} ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}}

\frac{d}{d x} (1 + x^{2}) = 2 x

\frac{d}{d x} ((1 - x^{2})^{2}) = - 4 x (1 - x^{2})

= 2 \cdot \frac{2 x ( 1 - x ^{2} ) ^{2} - ( - 4 x ( 1 - x ^{2} ) ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}}

Simplify

2 \cdot \frac{2 x ( 1 - x ^{2} ) ^{2} - ( - 4 x ( 1 - x ^{2} ) ) ( 1 + x ^{2} )}{( ( 1 - x ^{2} ) ^{2} ) ^{2}} : \frac{4 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

= \frac{4 x ( x ^{2} + 3 )}{( 1 - x ^{2} ) ^{3}}

\frac{\partial}{\partial x} (y^{6} cos (6 x))

\int z sin (8 z) d z

\frac{\partial}{\partial x} (x e^{x} cos (y))

\frac{d}{d x} (arcsin (5 x + 1))

n = 0 \sum \infty \frac{e n}{3 n + 1}

What is the derivative of (2(1+x^2)/((1-x^2)^2)) ?
The derivative of (2(1+x^2)/((1-x^2)^2)) is (4x(x^2+3))/((1-x^2)^3)
What is the first derivative of (2(1+x^2)/((1-x^2)^2)) ?
The first derivative of (2(1+x^2)/((1-x^2)^2)) is (4x(x^2+3))/((1-x^2)^3)