What is the limit as x approaches 0 of e^{-1/x} ?

The limit as x approaches 0 of e^{-1/x} is diverges

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limit as x approaches 0 of e^{-1/x}

x \to 0 lim (e^{- \frac{1}{x}})

diverges

Solution steps

x \to 0 lim (e^{- \frac{1}{x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (e^{- \frac{1}{x}}) = 0

x \to 0 - lim (e^{- \frac{1}{x}}) = \infty

= diverges

\frac{d y}{d x} = \frac{2 x y}{x ^{2} + y ^{2}}

\int (- 9 x^{2} + 9 x + 2) d x

y = (x^{3} + 8 x^{2})^{- 1}

f (x) = \frac{2 x + 5}{x - 1}

\int \frac{1}{x ^{4} 16 x ^{2} - 9} d x

What is the limit as x approaches 0 of e^{-1/x} ?
The limit as x approaches 0 of e^{-1/x} is diverges