What is (\partial)/(\partial x)(12x+2y-3x^2-y^2) ?

The answer to (\partial)/(\partial x)(12x+2y-3x^2-y^2) is -6x+12

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(\partial)/(\partial x)(12x+2y-3x^2-y^2)

\frac{\partial}{\partial x} (12 x + 2 y - 3 x^{2} - y^{2})

- 6 x + 12

Solution steps

\frac{\partial}{\partial x} (12 x + 2 y - 3 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (12 x) + \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (12 x) = 12

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 12 + 0 - 6 x - 0

Simplify

= - 6 x + 12

x + 7, 0.5 (x + 7), - 7, - 3

(8, 1230), (16, 2430)

\int e^{7 x} sin (x) d x

\frac{d}{d x} (ln (3 x^{4}))

\int 3 x^{2} - 4 x + 2 d x

What is (\partial)/(\partial x)(12x+2y-3x^2-y^2) ?
The answer to (\partial)/(\partial x)(12x+2y-3x^2-y^2) is -6x+12