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Popular >

y^'= y/t+2t+1

Solution

y^{^{'}} = \frac{y}{t} + 2 t + 1

Solution

y = 2 t^{2} + t ln (t) + c_{1} t

Solution steps

y^{'} (t) = \frac{y}{t} + 2 t + 1

Solve linear ODE:

y = 2 t^{2} + t ln (t) + c_{1} t

y = 2 t^{2} + t ln (t) + c_{1} t

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d/(d{x)}(({x)/y}{{z}})

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Frequently Asked Questions (FAQ)

What is the solution for y^'= y/t+2t+1 ?
The solution for y^'= y/t+2t+1 is y=2t^2+tln(t)+c_{1}t