What is the solution for dy-(y-4)^2dx=0 ?

The solution for dy-(y-4)^2dx=0 is y=-1/(x+c_{1)}+(4x)/(x+c_{1)}+(4c_{1})/(x+c_{1)}

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dy-(y-4)^2dx=0

d y - (y - 4)^{2} d x = 0

y = - \frac{1}{x + c _{1}} + \frac{4 x}{x + c _{1}} + \frac{4 c _{1}}{x + c _{1}}

Solution steps

d y - (y - 4)^{2} d x = 0

Solve separable ODE:

y = - \frac{1}{x + c _{1}} + \frac{4 x}{x + c _{1}} + \frac{4 c _{1}}{x + c _{1}}

y = - \frac{1}{x + c _{1}} + \frac{4 x}{x + c _{1}} + \frac{4 c _{1}}{x + c _{1}}

\frac{d}{d x} (cos^{2} (x s i) n^{2} x)

\frac{\partial}{\partial x} (x arcsin (x y))

f (x) = \frac{6}{x}

\frac{\partial}{\partial x} ((x - y)^{5})

y = \frac{8}{x ^{2} + 4}, (2, 1)

What is the solution for dy-(y-4)^2dx=0 ?
The solution for dy-(y-4)^2dx=0 is y=-1/(x+c_{1)}+(4x)/(x+c_{1)}+(4c_{1})/(x+c_{1)}