What is the integral from 1 to 2 of 1/8+3/8 x ?

The integral from 1 to 2 of 1/8+3/8 x is 11/16

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integral from 1 to 2 of 1/8+3/8 x

\int_{1}^{2} \frac{1}{8} + \frac{3}{8} x d x

\frac{11}{16}

Decimal Notation

0.6875

Solution steps

\int_{1}^{2} \frac{1}{8} + \frac{3}{8} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{8} d x + \int_{1}^{2} \frac{3}{8} x d x

\int_{1}^{2} \frac{1}{8} d x = \frac{1}{8}

\int_{1}^{2} \frac{3}{8} x d x = \frac{9}{16}

= \frac{1}{8} + \frac{9}{16}

Simplify

\frac{1}{8} + \frac{9}{16} : \frac{11}{16}

= \frac{11}{16}

\frac{d}{d x} ((3 x^{4} - x + 1) (- x^{5} + 4))

y^{^{'}} + 2 y = 1, y (0) = \frac{5}{2}

\int x (2 x + 3)^{2} d x

\frac{d y}{d x} = \frac{y cos ( x )}{1 - 2 y}

\frac{d}{d x} (12)

What is the integral from 1 to 2 of 1/8+3/8 x ?
The integral from 1 to 2 of 1/8+3/8 x is 11/16