What is the tangent of y=2x^3,(-3,-54) ?

The tangent of y=2x^3,(-3,-54) is y=54x+108

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tangent of y=2x^3,(-3,-54)

tangent of

y = 2 x^{3}, (- 3, - 54)

y = 54 x + 108

Solution steps

Find the slope of

y = 2 x^{3} : \frac{d y}{d x} = 6 x^{2}

Compute the slope of

y = 2 x^{3}

(- 3, - 54) : m = 54

Find the line with slope m=

54

and passing through

(- 3, - 54) : y = 54 x + 108

y = 54 x + 108

x \to - 5 lim (\frac{x + 4}{x + 5})

\int_{1}^{3} (x^{2} + 3)^{3} x d x

\int x x^{2} + 1 d x

\frac{\partial}{\partial x} (ln (2 x + 3 y))

(2, 9), (9, 2)

What is the tangent of y=2x^3,(-3,-54) ?
The tangent of y=2x^3,(-3,-54) is y=54x+108