What is the tangent of f(x)=6x^2 ?

The tangent of f(x)=6x^2 is y=12a_{0}x-6a_{0}^2

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tangent of f(x)=6x^2

tangent of

f (x) = 6 x^{2}

y = 12 a_{0} x - 6 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2})

Find the slope of

f (x) = 6 x^{2} : \frac{df ( x )}{d x} = 12 x

Compute the slope of

f (x) = 6 x^{2}

x = a_{0} : m = 12 a_{0}

Find the line with slope m=

12 a_{0}

and passing through

(a_{0}, 6 a_{0}^{2}) : y = 12 a_{0} x - 6 a_{0}^{2}

y = 12 a_{0} x - 6 a_{0}^{2}

x \to 3 - lim (ln x^{2} - 9)

\int (\frac{1 - cos ( 2 x )}{2})^{2} d x

ln ∣ ln (10 x) ∣

\frac{d}{d x} (x (x - 10)^{2})

What is the tangent of f(x)=6x^2 ?
The tangent of f(x)=6x^2 is y=12a_{0}x-6a_{0}^2