What is implicit 2x^2+xy+y^2=4 ?

The answer to implicit 2x^2+xy+y^2=4 is (dy)/(dx)=(-4x-y)/(x+2y)

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implicit 2x^2+xy+y^2=4

implicit derivative

2 x^{2} + x y + y^{2} = 4

\frac{d y}{d x} = \frac{- 4 x - y}{x + 2 y}

Solution steps

2 x^{2} + x y + y^{2} = 4

Treat

y

y (x)

Differentiate both sides:

4 x + y + x \frac{d y}{d x} + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 4 x - y}{x + 2 y}

\frac{d y}{d x} = \frac{- 4 x - y}{x + 2 y}

f (x) = \frac{x ^{2} - 4 x + 3}{x + 1}

\int \frac{1}{1 - tan ( 6 x )} d x

x \to 1 lim (x^{3} - 2 x^{2} - 7 x - 6)

x \to \infty lim ((- 1)^{x})

\int \frac{1}{4 t t ^{2} - 16} d t

What is implicit 2x^2+xy+y^2=4 ?
The answer to implicit 2x^2+xy+y^2=4 is (dy)/(dx)=(-4x-y)/(x+2y)