What is the derivative of 2^x+cos(3x) ?

The derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3

What is the first derivative of 2^x+cos(3x) ?

The first derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2^{x} + cos (3 x))

2^{x} ln (2) - sin (3 x) \cdot 3

Solution steps

\frac{d}{d x} (2^{x} + cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= 2^{x} ln (2) - sin (3 x) \cdot 3

\int \frac{sin ( 2 x )}{47 + cos ^{2} ( x )} d x

y = \frac{6 x}{x ^{2} + 1}, (- 1, - 3)

(3 x)^{^{'}}

\frac{\partial}{\partial x} (y^{2} cos (y))

What is the derivative of 2^x+cos(3x) ?
The derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3
What is the first derivative of 2^x+cos(3x) ?
The first derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3