What is the integral of (10)/(\sqrt[3]{x^2)} ?

The integral of (10)/(\sqrt[3]{x^2)} is 30\sqrt[3]{x}+C

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integral of (10)/(\sqrt[3]{x^2)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 10 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 10 \cdot 3 x^{\frac{1}{3}}

Simplify

Add a constant to the solution

\frac{d}{d x} (\frac{v}{x})

\frac{d}{d x} (\frac{x ^{3}}{x - 1})

\frac{s - 1}{s ^{2} + 4 s + 5}

\frac{\partial}{\partial x} (e^{- 5 x} cos (7 π t))

\int sin (2 x) - cos (x) d x

What is the integral of (10)/(\sqrt[3]{x^2)} ?
The integral of (10)/(\sqrt[3]{x^2)} is 30\sqrt[3]{x}+C