What is the derivative of cos(2x+pi) ?

The derivative of cos(2x+pi) is 2sin(2x)

What is the first derivative of cos(2x+pi) ?

The first derivative of cos(2x+pi) is 2sin(2x)

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\frac{d}{d x} (cos (2 x + π))

2 sin (2 x)

Solution steps

\frac{d}{d x} (cos (2 x + π))

Simplify

cos (2 x + π) : - cos (2 x)

= \frac{d}{d x} (- cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - (- sin (2 x) \cdot 2)

Simplify

= 2 sin (2 x)

\int \frac{1}{( 1 - x ) ^{3}} d x

(9 - 2 x^{3})^{3}

\frac{d}{d x} (x^{r})

\frac{d}{d x} (e^{x^{2} - y^{2}} sin (2 x y))

\int cos (1 - x) d x

What is the derivative of cos(2x+pi) ?
The derivative of cos(2x+pi) is 2sin(2x)
What is the first derivative of cos(2x+pi) ?
The first derivative of cos(2x+pi) is 2sin(2x)