What is (\partial)/(\partial x)(6/(x-2)+7x) ?

The answer to (\partial)/(\partial x)(6/(x-2)+7x) is -6/((x-2)^2)+7

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(\partial)/(\partial x)(6/(x-2)+7x)

\frac{\partial}{\partial x} (\frac{6}{x - 2} + 7 x)

- \frac{6}{( x - 2 ) ^{2}} + 7

Solution steps

\frac{\partial}{\partial x} (\frac{6}{x - 2} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{6}{x - 2}) + \frac{\partial}{\partial x} (7 x)

\frac{\partial}{\partial x} (\frac{6}{x - 2}) = - \frac{6}{( x - 2 ) ^{2}}

\frac{\partial}{\partial x} (7 x) = 7

= - \frac{6}{( x - 2 ) ^{2}} + 7

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y = e^{x}, (1, e)

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What is (\partial)/(\partial x)(6/(x-2)+7x) ?
The answer to (\partial)/(\partial x)(6/(x-2)+7x) is -6/((x-2)^2)+7