What is the derivative of x^3-3x^2-2x+1 ?

The derivative of x^3-3x^2-2x+1 is 3x^2-6x-2

What is the first derivative of x^3-3x^2-2x+1 ?

The first derivative of x^3-3x^2-2x+1 is 3x^2-6x-2

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\frac{d}{d x} (x^{3} - 3 x^{2} - 2 x + 1)

3 x^{2} - 6 x - 2

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} - 6 x - 2 + 0

Simplify

= 3 x^{2} - 6 x - 2

\frac{d}{d x} (3 x^{- 3})

\int t^{2} - 2 t^{4} d t

f (x) = \frac{4 x + 3}{4 x - 3}

\int_{- 3}^{3} \frac{16}{x ^{2} - 6 x - 55} d x

\frac{d}{d x} ((1 - e^{x}) (x + e^{x}))

What is the derivative of x^3-3x^2-2x+1 ?
The derivative of x^3-3x^2-2x+1 is 3x^2-6x-2
What is the first derivative of x^3-3x^2-2x+1 ?
The first derivative of x^3-3x^2-2x+1 is 3x^2-6x-2