What is the d/(dv)(sqrt(u/v)) ?

The d/(dv)(sqrt(u/v)) is -(sqrt(u))/(2v^{3/2)}

What is the first d/(dv)(sqrt(u/v)) ?

The first d/(dv)(sqrt(u/v)) is -(sqrt(u))/(2v^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d v} (\frac{u}{v})

- \frac{u}{2 v ^{\frac{3}{2}}}

Solution steps

\frac{d}{d v} (\frac{u}{v})

Treat

u

as a constant

Apply the chain rule:

\frac{1}{2 \frac{u}{v}} \frac{d}{d v} (\frac{u}{v})

= \frac{1}{2 \frac{u}{v}} \frac{d}{d v} (\frac{u}{v})

\frac{d}{d v} (\frac{u}{v}) = - \frac{u}{v ^{2}}

= \frac{1}{2 \frac{u}{v}} (- \frac{u}{v ^{2}})

Simplify

\frac{1}{2 \frac{u}{v}} (- \frac{u}{v ^{2}}) : - \frac{u}{2 v ^{\frac{3}{2}}}

= - \frac{u}{2 v ^{\frac{3}{2}}}

x \to 0 lim ((1 + 7 x)^{\frac{5}{x}})

\frac{\partial}{\partial y} (- x e^{- 3 x y})

\int_{0}^{1} (1 + x)^{3} d x

y = 3 x - x^{2}, y = - 4 x

\int \frac{8}{9 + 3 x} d x

What is the d/(dv)(sqrt(u/v)) ?
The d/(dv)(sqrt(u/v)) is -(sqrt(u))/(2v^{3/2)}
What is the first d/(dv)(sqrt(u/v)) ?
The first d/(dv)(sqrt(u/v)) is -(sqrt(u))/(2v^{3/2)}