What is the solution for t^3(dy)/(dt)+3t^2y=3cos(t),y(pi)=0 ?

The solution for t^3(dy)/(dt)+3t^2y=3cos(t),y(pi)=0 is y=(3sin(t))/(t^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t^3(dy)/(dt)+3t^2y=3cos(t),y(pi)=0

t^{3} \frac{d y}{d t} + 3 t^{2} y = 3 cos (t), y (π) = 0

y = \frac{3 sin ( t )}{t ^{3}}

Solution steps

t^{3} \frac{d y}{d t} + 3 t^{2} y = 3 cos (t)

Solve linear ODE:

y = \frac{3 sin ( t )}{t ^{3}}

y = \frac{3 sin ( t )}{t ^{3}}

\int \frac{5 x ^{4} - 2}{x ^{5} - 2 x + 11} d x

y^{^{'}} + 3 y = e^{5 t}

x \to - 2 lim (- \frac{x ^{2} - 4}{x + 2})

\int x e^{m x} d x

x \to 0 lim (\frac{e ^{5 x} - 1}{x})

What is the solution for t^3(dy)/(dt)+3t^2y=3cos(t),y(pi)=0 ?
The solution for t^3(dy)/(dt)+3t^2y=3cos(t),y(pi)=0 is y=(3sin(t))/(t^3)