What is the d/(dt)(t-\sqrt[3]{t}) ?

The d/(dt)(t-\sqrt[3]{t}) is 1-1/(3t^{2/3)}

What is the first d/(dt)(t-\sqrt[3]{t}) ?

The first d/(dt)(t-\sqrt[3]{t}) is 1-1/(3t^{2/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 - \frac{1}{3 t ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d t}{d t} = 1

= 1 - \frac{1}{3 t ^{\frac{2}{3}}}

\frac{d}{d x} ((\frac{1 - cos ( x )}{1 + cos ( x )})^{3})

x \to - 2 - lim (6 x + 5)

\frac{\partial}{\partial y} (x e^{x + y})

x \to 0 lim (\frac{5 - 5 sin ( x )}{x})

\frac{d}{d x} ((5 x + 2)^{2})

What is the d/(dt)(t-\sqrt[3]{t}) ?
The d/(dt)(t-\sqrt[3]{t}) is 1-1/(3t^{2/3)}
What is the first d/(dt)(t-\sqrt[3]{t}) ?
The first d/(dt)(t-\sqrt[3]{t}) is 1-1/(3t^{2/3)}