What is the derivative of tanh(x^2-9) ?

The derivative of tanh(x^2-9) is sech^2(x^2-9)*2x

What is the first derivative of tanh(x^2-9) ?

The first derivative of tanh(x^2-9) is sech^2(x^2-9)*2x

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\frac{d}{d x} (tanh (x^{2} - 9))

sech^{2} (x^{2} - 9) \cdot 2 x

Solution steps

\frac{d}{d x} (tanh (x^{2} - 9))

Apply the chain rule:

sech^{2} (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

= sech^{2} (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= sech^{2} (x^{2} - 9) \cdot 2 x

x \to 7 lim (x^{4})

\int (6 x - 5) (3 x^{2} - 5 x)^{3} d x

\int y^{\frac{3}{2}} d y

ln (cos (t))

\frac{d}{d x} ((x^{2} - 5 x)^{4})

What is the derivative of tanh(x^2-9) ?
The derivative of tanh(x^2-9) is sech^2(x^2-9)*2x
What is the first derivative of tanh(x^2-9) ?
The first derivative of tanh(x^2-9) is sech^2(x^2-9)*2x