What is the solution for y^'+1/x y= 2/3 x^4y^4 ?

The solution for y^'+1/x y= 2/3 x^4y^4 is y= 1/(x\sqrt[3]{-x^2+c_{1)}}

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y^'+1/x y= 2/3 x^4y^4

y^{^{'}} + \frac{1}{x} y = \frac{2}{3} x^{4} y^{4}

Solution steps

y^{'} (x) + \frac{1}{x} y = \frac{2}{3} x^{4} y^{4}

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What is the solution for y^'+1/x y= 2/3 x^4y^4 ?
The solution for y^'+1/x y= 2/3 x^4y^4 is y= 1/(x\sqrt[3]{-x^2+c_{1)}}