What is the derivative of 9/((x-8^2)) ?

The derivative of 9/((x-8^2)) is -(18)/((x-8)^3)

What is the first derivative of 9/((x-8^2)) ?

The first derivative of 9/((x-8^2)) is -(18)/((x-8)^3)

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\frac{d}{d x} (\frac{9}{( x - 8 ) ^{2}})

- \frac{18}{( x - 8 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{9}{( x - 8 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{( x - 8 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((x - 8)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 8 ) ^{3}} \frac{d}{d x} (x - 8)

= - \frac{2}{( x - 8 ) ^{3}} \frac{d}{d x} (x - 8)

\frac{d}{d x} (x - 8) = 1

= 9 (- \frac{2}{( x - 8 ) ^{3}} \cdot 1)

Simplify

9 (- \frac{2}{( x - 8 ) ^{3}} \cdot 1) : - \frac{18}{( x - 8 ) ^{3}}

= - \frac{18}{( x - 8 ) ^{3}}

\frac{\partial}{\partial x} (3 x^{2} - 24 y)

\frac{d}{d x} (- 2 ln (x))

\frac{d}{d x} ((x - 2)^{3} (x - 6))

5 x, \frac{5}{x}, x = 5

\frac{d}{d x} ((x - 1)^{\frac{1}{3}} (x + 2)^{\frac{2}{3}})

What is the derivative of 9/((x-8^2)) ?
The derivative of 9/((x-8^2)) is -(18)/((x-8)^3)
What is the first derivative of 9/((x-8^2)) ?
The first derivative of 9/((x-8^2)) is -(18)/((x-8)^3)