What is the derivative of y=x^2+4x-3 ?

The derivative of y=x^2+4x-3 is 2x+4

What is the first derivative of y=x^2+4x-3 ?

The first derivative of y=x^2+4x-3 is 2x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{2} + 4 x - 3

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (3) = 0

= 2 x + 4 - 0

Simplify

= 2 x + 4

\int sin (16 x) cos (11 x) d x

\frac{d N}{d t} = 5 - N

\frac{2 x + x ^{2}}{( 1 + x ) ^{2}}

\frac{d y}{d x} = \frac{x - y}{x + 2 y}

(9 + x) \frac{d y}{d x} = 6 + x

What is the derivative of y=x^2+4x-3 ?
The derivative of y=x^2+4x-3 is 2x+4
What is the first derivative of y=x^2+4x-3 ?
The first derivative of y=x^2+4x-3 is 2x+4