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Popular >

xy^'=y^2,y(1)=1

Solution

x y^{^{'}} = y^{2}, y (1) = 1

Solution

y = - \frac{1}{ln ( x ) - 1}

Solution steps

x y^{'} (x) = y^{2}

Solve separable ODE:

y = - \frac{1}{ln ( x ) - 1}

y = - \frac{1}{ln ( x ) - 1}

Popular Examples

t \cdot y^{^{'}} - 3 \cdot y = t^{4}

laplacetransform (t+2)^2e^t laplace transform

(t + 2)^{2} e^{t}

laplacetransform t*e^{-t}laplace transform

t \cdot e^{- t}

f (x) = x^{3} e^{x}

integral of 1/(2x^2-4x+12)

\int \frac{1}{2 x ^{2} - 4 x + 12} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'=y^2,y(1)=1 ?
The solution for xy^'=y^2,y(1)=1 is y=-1/(ln(x)-1)