What is the tangent of y=-3-7x^2 ?

The tangent of y=-3-7x^2 is y=-14a_{0}x-3+7a_{0}^2

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tangent of y=-3-7x^2

tangent of

y = - 3 - 7 x^{2}

y = - 14 a_{0} x - 3 + 7 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 - 7 a_{0}^{2})

Find the slope of

y = - 3 - 7 x^{2} : \frac{d y}{d x} = - 14 x

Compute the slope of

y = - 3 - 7 x^{2}

x = a_{0} : m = - 14 a_{0}

Find the line with slope m=

- 14 a_{0}

and passing through

(a_{0}, - 3 - 7 a_{0}^{2}) : y = - 14 a_{0} x - 3 + 7 a_{0}^{2}

y = - 14 a_{0} x - 3 + 7 a_{0}^{2}

\frac{d}{d x} (3^{4 x^{2} + 3 x})

\frac{\partial}{\partial x} (2 e^{x^{2}})

x \to 0 lim (\frac{14}{x})

\frac{10}{( s \cdot ( s + 1 ) )}

What is the tangent of y=-3-7x^2 ?
The tangent of y=-3-7x^2 is y=-14a_{0}x-3+7a_{0}^2