What is laplacetransform s+2 ?

The answer to laplacetransform s+2 is 1/(s^2)+2/s

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laplacetransform s+2

laplace transform

s + 2

\frac{1}{s ^{2}} + \frac{2}{s}

Solution steps

L {s + 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {s} + L {2}

L {s} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} + \frac{2}{s}

\frac{d}{d x} (6 x^{2} y - 3 x y^{2})

\int (5 x^{3}) d x

f (x) = - \frac{6}{( 3 x + 5 ) ^{2}}, at x = - 1

f (x) = x^{2} - 1

\int \frac{x ^{3}}{x ^{4} - 2} d x

What is laplacetransform s+2 ?
The answer to laplacetransform s+2 is 1/(s^2)+2/s