What is the derivative of g(w)=12\sqrt[3]{w} ?

The derivative of g(w)=12\sqrt[3]{w} is 4/(w^{2/3)}

What is the first derivative of g(w)=12\sqrt[3]{w} ?

The first derivative of g(w)=12\sqrt[3]{w} is 4/(w^{2/3)}

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derivative of

\frac{4}{w ^{\frac{2}{3}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply radical rule:

= 12 \frac{d}{d w} (w^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 12 \cdot \frac{1}{3} w^{\frac{1}{3} - 1}

Simplify

12 \cdot \frac{1}{3} w^{\frac{1}{3} - 1} : \frac{4}{w ^{\frac{2}{3}}}

= \frac{4}{w ^{\frac{2}{3}}}

f (x) = \frac{1}{x - 2}

\frac{\partial}{\partial x} (\frac{- 4 x ^{5}}{4 y ^{4}})

\frac{d y}{d x} y = x

- x^{2} + 3 x + 7

\frac{d}{d y} (\frac{y}{z})

What is the derivative of g(w)=12\sqrt[3]{w} ?
The derivative of g(w)=12\sqrt[3]{w} is 4/(w^{2/3)}
What is the first derivative of g(w)=12\sqrt[3]{w} ?
The first derivative of g(w)=12\sqrt[3]{w} is 4/(w^{2/3)}