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Popular >

f^'(x)=2x^3-x

Solution

f^{^{'}} (x) = 2 x^{3} - x

Solution

f (x) = \frac{x ^{4}}{2} - \frac{x ^{2}}{2} + c_{1}

Solution steps

f^{'} (x) = 2 x^{3} - x

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 2 x^{3} - x d x

\int 2 x^{3} - x d x = \frac{x ^{4}}{2} - \frac{x ^{2}}{2} + c_{1}

f (x) = \frac{x ^{4}}{2} - \frac{x ^{2}}{2} + c_{1}

Popular Examples

derivative of y=ce^{(-x^3)/3}+1 derivative of

y = c e^{\frac{- x ^{3}}{3}} + 1

integral from 1 to 5 of 6250pix

\int_{1}^{5} 6250 π x d x

derivative of f(x)=x^3+x derivative of

f (x) = x^{3} + x

tangent of 2sqrt(x),\at x=9 tangent of

2 x, at x = 9

tangent of f(x)=(8x)/(x^2-1),\at x=3 tangent of

f (x) = \frac{8 x}{x ^{2} - 1}, at x = 3

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=2x^3-x ?
The solution for f^'(x)=2x^3-x is f(x)=(x^4)/2-(x^2)/2+c_{1}