What is the integral of 4sin(5x) ?

The integral of 4sin(5x) is -4/5 cos(5x)+C

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integral of 4sin(5x)

\int 4 sin (5 x) d x

- \frac{4}{5} cos (5 x) + C

Solution steps

\int 4 sin (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sin (5 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{5} d u

= 4 \cdot \int sin (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{5} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 4 \cdot \frac{1}{5} (- cos (u))

Substitute back

u = 5 x

= 4 \cdot \frac{1}{5} (- cos (5 x))

Simplify

4 \cdot \frac{1}{5} (- cos (5 x)) : - \frac{4}{5} cos (5 x)

= - \frac{4}{5} cos (5 x)

Add a constant to the solution

= - \frac{4}{5} cos (5 x) + C

\int \frac{1}{x ^{\frac{2}{3}} ( 8 + x ^{\frac{1}{3}} )} d x

y (θ) = ln (θ + 1) - e^{θ}

\frac{\partial}{\partial x} (ln (x + y) - 5 y)

\frac{d}{d x} ((x + 3)^{x})

\frac{d}{d x} (x^{5 e^{x}})